Fundamentals, C arrays and pointers

Why C arrays are not pointers? Well, by definition

In C, there is a strong relationship between pointers and arrays, strong enough that pointers and arrays should be discussed simultaneously. (K&R)

They are easy to mix up

When an array name is passed to a function, what is passed is the location of the initial element. (K&R)

An example

#include <stdio.h>

void func(char subarray[100], char* pointer) {
    printf("sizeof subarray=%zd\n", sizeof(subarray));
    printf("address of subarray=%p\n", (void *)subarray);
    printf("pointer=%p\n", (void *)pointer);
}

int main() {
    char array[100];
    printf("sizeof of array=%zd\n", sizeof(array));
    printf("address of array=%p\n", (void *)array);
    printf("address of array[0]=%p\n", (void *)&array[0]);
    func(array, array);
}

// ----------------------------------------

sizeof of array=100
address of array=0xbfbfe760
address of array[0]=0xbfbfe760
sizeof subarray=4
address of subarray=0xbfbfe760
pointer=0xbfbfe760